1. $date1 = “2017-03-24″;  
2. $date2 = “2019-06-26″;  
3.   
4. $diff = abs(strtotime($date2) - strtotime($date1));  
5.   
6. $years = floor($diff / (365*60*60*24));  
7. $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));  
8. $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));  
9.   
10. printf(“%d years, %d months, %d days\n”, $years, $months, $days);  

$date1 = “2017-03-24″;<br /> $date2 = “2019-06-26″;</p> <p>$diff = abs(strtotime($date2) – strtotime($date1));</p> <p>$years = floor($diff / (365*60*60*24));<br /> $months = floor(($diff – $years * 365*60*60*24) / (30*60*60*24));<br /> $days = floor(($diff – $years * 365*60*60*24 – $months*30*60*60*24)/ (60*60*24));</p> <p>printf(“%d years, %d months, %d days\n”, $years, $months, $days);